Algebraic dimension over frobenius fields

Moshe Jarden*

*Corresponding author for this work

Research output: Contribution to journalArticlepeer-review

5 Scopus citations


We prove that each perfect Frobenius field is algebraically bounded and hence has a dimension function in the sense of v.d. Dries on the collection of all definable sets. Given a definable set S over Q (resp. Fp) we can effectively determine for each k ∊ {—∞,0,1,…} whether there exists a perfect Frobenius field M of characteristic 0 (resp., of characteristic p) such that the dimension of S(M) is k. Our method of proof and decision procedure is based on Galois Stratification.

Original languageEnglish
Pages (from-to)43-64
Number of pages22
JournalForum Mathematicum
Issue number6
StatePublished - 1994


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